Balance the chemical equation given below, and determine the number of grams of MgO that are needed to produce 20.0 g of Fe2O3. MgO(s) Fe(s) Fe2O3(s) Mg(s)

1.) The balanced equation is    3MgO(s) +  2Fe(s) ===> Fe2O3(s) + 3Mg(s)

2.) 20g of Fe2O3 will be produced by 20 ×120/160 = 15g of MgO

Explanation:

THE CORRECT EQUATION IS: MgO(s) + ___ Fe(s)  ===> Fe2O3(s) + ___ Mg(s)

The balanced equation is: 3MgO(s) +  2Fe(s) ===> Fe2O3(s) + 3Mg(s)

molar mass of 3MgO = 3(24 + 16) = 120

Molar mass of Fe2O3 = 2 X 56 + 3 X 16

                                    =112 +48 =160

From the equation, 120g of MgO Produced 160g of Fe2O3

Therefore 20g of Fe2O3 will be produced by 20 ×120/160 = 15g of MgO.

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boiling point is the temperature at which the vapor pressure of the liquid equals atmospheric pressure. the vapor pressure of solvent molecules is decreased when a solute is added, so a higher temperature is required to increase the number of solvent molecules in the gas phase above the liquid.

at the freezing point, the vapor pressures of the solid and liquid are equal; a lower temperature is needed to reduce the number of solvent particles above the liquid.

hope this you

tobey

nacl is added to the aqueous of what? ? in order to get a proper answer you have to specify the exact composition of the aqueous solution.