A typical sample of vinegar has a pH of 3.0. Assuming that vinegar is only an aqueous solution of acetic acid (Ka=1.8x10^-5), calculate the concentration of acetic acid in vinegar.

Concentration of acetic acid in vinegar is 0.06 M

Explanation:

     cM              0             0

So dissociation constant will be:

Putting in the values we get:

Thus concentration of acetic acid in vinegar is 0.06 M

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.

so what is the problem with your lab report and whats the subject of the lab report? i will you