If you wanted to shift the potential of the lead-zinc cell upward, toward 0.70 V, which of the following actions would give thedesired result? Check all that apply. *Ignore the currentchecks.
Anyaction that makes [Zn2+] smaller than[Pb2+].
Any action that makes [Zn2+]larger than [Pb2+].
Adding some concentratedZn(C2H3O2)2 solution tothe Zn2+/Zn couple.
Anyaction that makes Q > 1.0.
Addingsome concentratedPb(C2H3O2)2 solution tothe Pb2+/Pb couple.
Anyaction that makes log Q positive.
Any action that makes log Qnegative.
Any action that makes Q <1.0.

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied