As a research assistant, you are asked to prepare a 3.00 liter solution of magnesium sulfate at 45.0 micromoles per liter. How many moles of magnesium sulfate are required to make this solution?

Explanation:

From the question given, we obtained the following:

Molarity = 45.0 micromoles per liter = 45x10^-6mol/L

Volume = 3L

Mole =?

Molarity = mole /Volume

Mole = Molarity x Volume

Mole = 45x10^-6 x 3

Mole = 1.35x10^-4 moles

Therefore, 1.35x10^-4 moles of magnesium sulfate is needed to make the solution.

in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.