An unknown gas effuses at 0.770 times the effusion rate of nitrogen dioxide (NO2). Estimate the molar mass of the unknown gas. Answer in units of g/mol.

77.58g/mol

Explanation:

Let the rate of effusion of NO2 be R1

The rate of effusion of the unknown gas(R2) = 0.770R1

Molar Mass of NO2 (M1) = 14 + (2x16) = 14 + 32 = 46g/mol

The molar mass of the unknown gas (M2) =?

R1/R2 = √(M2/M1)

R1/0.770R1 = √(M2/46)

1/0.770 = √(M2/46)

Take the square of both sides

(1/0.770)^2 = M2/46

Cross multiply to express in linear form

M2 = (1/0.770)^2 x 46

M2 = 77.58g/mol

The molar mass of the unknown gas is 77.58g/mol

- calcium has greater affinity to bond with electron receptors than hydrogen does and hence, it has the ability to replace hydrogen in most of its compounds.

- lithium has 2 valence electrons in the product because it can make only 1 bond with hydrogen. beryllium has 4 valence electrons in the product because it can only make 2 bonds. it has fewer electrons than neon and can react with electron donors. each hydrogen has 2 valence electrons, the same as helium.

- the covalent bond formed between carbon and hydrogen is polar because carbon is more electronegative than hydrogen and it attracts the bonded electron pair closer to itself, thus giving hydrogen a partial positive charge.

- a hydrogen bond is a relatively weak bond that hydrogen atoms make with the electronegative atoms nitrogen, oxygen or fluorine.

so the best choice is a.) 2 calcium (ca) atoms

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