Chemistry, 07.03.2020 02:54 ljadalyn

In the following acid-base reactions, identify the spectator ions, if any:
(i) Cesium hydroxide(aq) + nitric acid(aq) =>
(ii) Calcium hydroxide(aq) + acetic acid(aq) =>
a.
(i) Cs+ and NO3-
(ii) no spectator ions
b.
(i) Cs+ and NO3-
(ii) H+ and OH-
c.
(i) no spectator ions
(ii) H+ and OH-
d.
(i) Cs+ and NO3-
(ii) Ca2+ and acetate ion.
e.
(i) no spectator ions
(ii) no spectator ions

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Answer from: ranaawilliamsoowl6dk

Answer : The correct option is, (d)

(i) $Cs^+,\text{ and }NO_3^-$

(ii) $Ca^{2+},\text{ and }CH_3COO^-$

Explanation :

Complete ionic equation : In complete ionic equation, all the substance that are strong electrolyte and present in an aqueous are represented in the form of ions.

Net ionic equation : In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

(i) The balanced molecular equation will be,

$CsOH(aq)+HNO_3(aq)\rightarrow CsNO_3(aq)+H_2O(l)$

The complete ionic equation in separated aqueous solution will be,

$Cs^+(aq)+OH^{-}(aq)+H^{+}(aq)+NO_3^{-}(aq)\rightarrow Cs^+(aq)+NO^{3-}(aq)+H_2O(l)$

In this equation the species $Cs^+,\text{ and }NO_3^-$ are the spectator ions.

(ii) The balanced molecular equation will be,

$Ca(OH)_2(aq)+2CH_3COOH(aq)\rightarrow Ca(CH_3COO)_2(aq)+H_2O(l)$

The complete ionic equation in separated aqueous solution will be,

$Ca^{2+}(aq)+2OH^{-}(aq)+2H^{+}(aq)+2CH_3COO^{-}(aq)\rightarrow Ca^{2+}(aq)+2CH_3COO^{-}(aq)+H_2O(l)$

In this equation the species $Ca^{2+},\text{ and }CH_3COO^-$ are the spectator ions.

Hence, the correct option is, (d)

(i) $Cs^+,\text{ and }NO_3^-$

(ii) $Ca^{2+},\text{ and }CH_3COO^-$

Answer from: Quest

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Answer from: Quest

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

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In the following acid-base reactions, identify the spectator ions, if any:
(i) Cesium hydroxid...