The unbalanced equation for the reduction of copper(I) sulfide with oxygen is given below. What mass of copper is produced from the reduction of 8.80 g Cu2S

The mass of copper produced is 7.12 grams

Explanation:

To calculate the number of moles, we use the equation:

    .....(1)

Given mass of copper (I) sulfide = 8.80 g

Molar mass of copper (I) sulfide = 156.2 g/mol

Putting values in equation 1, we get:

The chemical equation for the reaction of copper (I) sulfide and oxygen gas follows:

By Stoichiometry of the reaction:

1 mole of copper (I) sulfide produces 2 moles of copper

So, 0.056 moles of copper (I) sulfide will produce = of copper

Now, calculating the mass of copper from equation 1, we get:

Molar mass of copper = 63.55 g/mol

Moles of copper = 0.112 moles

Putting values in equation 1, we get:

Hence, the mass of copper produced is 7.12 grams

b

explanation:

mitosis

the product of the pressure and volume is also constant