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Chemistry, 06.03.2020 23:38 sophiaa23

The ionization energy for rubidium is 403 kJ/mol. The electron affinity for iodine is -295 kJ/mol. Use these values and Hess's law to calculate the change in enthalpy for the following reaction per mole of reagent:
Rb(g) + I(g) > Rb+(g)+I−(g), ΔH=?

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The ionization energy for rubidium is 403 kJ/mol. The electron affinity for iodine is -295 kJ/mol. U...
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