A 0.75M solution of CH3OH is prepared in 0.500 kg of water. How many moles of CH3OH are needed?

We need 0.375 mol of CH3OH to prepare the solution

Explanation:

For the problem they give us the following data:

Solution concentration 0,75 M

Mass of Solvent is 0,5Kg

knowing that the density of water is 1g / mL,  we find the volume of water:

Now, find moles of are needed using the molarity equation:

therefore the solution is prepared using 0.5 L of H2O and 0.375 moles of CH3OH,  resulting in a concentration of 0,75M

explanation:

i think option no d is the correct answer

20 drops hope this