A 10.0 mL 10.0 mL aliquot is removed from the described stock solution and diluted to a total volume of 100.0 mL. 100.0 mL. Calculate the molarity of the dilute solution.

The molarity of the dilute solution is 0.5 M.

The given parameters;

The molarity of the dilute solution is calculated as follows;

where;

D.F is dilute factor

The dilute factor of the given solution is calculated as follows;

Thus, the molarity of the dilute solution is 0.5 M.

"Your question is incomplete, it seems to be missing the following information":

A 10.0 mL of a liquid is removed from the described stock solution with molarity of 5M and diluted to a total volume of 100.0 mL. Calculate the molarity of the dilute solution.

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The given question is incomplete. The complete question is:

A 10.0 mL aliquot is removed from the described stock solution with molarity of 5M and diluted to a total volume of 100.0 mL. Calculate the molarity of the dilute solution.

0.5 M

Explanation:

where,

= molarity of stock solution = 5 M

= volume of stock solution = 10.0 ml ml

= molarity of dilute solution = ?

= volume of  dilute solution = 100.0 ml

Putting in the values we get:  

Thus the molarity of the dilute solution is 0.5 M

answer: i dont know the answer but this might

explanation:

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nuclear fission produces elements that are heavier than helium.

the elements that are used in nuclear fission and their products are much heavier than helium.