A moist soil sample weighing 5 lb has a moisture content of 2%. How many mL of water must be added to the sample to increase the moisture content to 10%? (This calculation is needed for your Compaction lab)

The answer is 181.437 ml of water to increase the soil's moisture content to 10%.

Explanation:

We have been given:

Soil weight = 5 lb = 2.26796 kg

2% of moisture ⇒ × 2.26796    =    0.045359 kg of water in the soil

10% of moisture ⇒ × 2.26796    = 0.226796 kg of water in the soil

The difference in moisture content = (0.226796 - 0.045359) kg

=0.181432 kg

But 1kg = 1000 ml

∴ 0.181437 kg = 181.437 ml of water required to increase the moisture content to 10%

100c is waters boiling point