The normal freezing point of a certain liquid Y is -8.70°C, but when 24.17g of urea (NH2)2CO are dissolved in 550 g of Y, it is found that the solution freezes at -13.7°C instead. Use this information to calculate the molal freezing point depression constant Kf of substance Y.

6.8 ºC m⁻¹

Explanation:

The strategy here is to use the equation for the freezing point depression

ΔTf = Kf x m   ⇒   Kf = ΔTf / m

where  k is the freezing point depression constant,ΔTf  is the change in the freezing point of the solution ( freezing point pure solvent minus freezing point of the solution), and m is the molality, mol of solute per kilogram solvent.

Thus

ΔTf (ºC) = -8.7 ºC - ( -13.7 )C  =  5.0 ºC

mol (NH₂)₂CO = mass / molar mass = 24.17 g / 60.06 gmol⁻¹ = 0.40 mol

m = 0.40 mol / 0.550 Kg = 0.73 m

Kf = ΔTf / m =  5.0 ºC / 0.73 m = 6.8 ºCm⁻¹

smooth muscle is composed of involuntary muscles found within the walls of organs and structures such as the esophagus, stomach, intestines, and blood vessels. those muscles push materials like food or blood through organs. unlike skeletal muscle, smooth muscle can never be under your control.

answer: e.   sour taste

explanation: acids are those substances which dissociates in water to give ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. acids are sour in taste. example: hcl

bases are those substances which dissociates in water to give ions or accepts ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. bases are bitter in taste. bases are slippery in nature.