Hydrochloric acid is purchased in 12 molar concentrations. If I needed 200 ml of 2.0 molar HCl, how many milliliters of the concentrated solution would I need

The answer to your question is 33.3 ml

Explanation:

Data

Stock solution 12M

Volume 2 = 200 ml

Concentration 2 = 2 M

Volume stock = ?

Process

1.- Use the formula for dilutions

                               C1V1 = C2 V2

- Solve for V1

                               V1 = C2V2 / C1

2.- Substitution

                               V1 = (2)(200) / 12

- Simplification

                               V1 = 400 / 12

3.- Result

                               V1 = 33.3 ml

4.- Conclusion

We need 33.3 ml of the concentrated solution.

ca has a crystalline lattice with positive ions (since it is a metal, metals are positively charged) and electrons flow freely in its structure since the ca atoms have a large nuclear radius so the electrons are not tightly held, therefore the electrons can flow freely since they are not being highly attracted by the nucleus. moreover, one of the properties of metals are that they are conductors of electricity, thus proving ca is the element.