A beam of 16 MeV deuterons from a cyclotron strikes a copper block. The beam is equivalent to current of 15 μA. (a) At what rate do deuterons strike the block? (b) At what rate is thermal energy produced in the block

(a)  9.4 X 10¹³s⁻¹

(b) 240 W

Explanation:

Given-

Current, i = 15μA

Electrons, e = 16 MeV

(a) The rate at which the deuterons strike the block, r = ?

We know,

Therefore, the rate at which the deuterons strike the block is 9.4 X 10¹³s⁻¹

(b) Rate at which thermal energy is produced in the block

Now that we have , we can use it with the equation of power to solve for the thermal energy production rate.

Therefore, the rate at which thermal energy is produced in the block is 240 W.

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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i think so it’s will be b yes i believe its