A solution has a [OH−] of 1 x 10−9. What is the pOH of this solution?

a) 5

b) 7

c) 9

d) 12

C) 9

General Formulas and Concepts:

Math

Algebra I

Logarithms

Chemistry

Acid-Base Equilibrium

Acid/BasesTitrationspH and pOH: take -log of concentrationExplanation:

Step 1: Define

[OH⁻] = 1 × 10⁻⁹ M

Step 2: Find pOH

Simply take negative log₁₀ of the concentration.

Set up:                                                                                                             pOH = -log(1 × 10⁻⁹ M)Evaluate:                                                                                                         pOH = 9