Your TA gave you 1 H NMR spectra of your product and iodotyrosine. Using the 1 H NMR spectra and the data given in the special section (p44 and 45), determine the structure of your product - i. E. Do you have ortho-bromo-4-tert-butylphenol, or meta-bromo-4-tert-butylphenol? Explain (using the 1 H NMR) how you came to your decision

there are two significant figures.

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.