At what temperature will .07 moles of CL2 exert a pressure of 1.18 atm at a volume of 750 mL? K

T = 154 K

Explanation:

Given data:

Number of moles of Cl₂ = 0.07 mol

Pressure = 1.18 atm

Volume = 750 mL

Temperature = ?

Solution:

The given problem will be solve by using general gas equation, which is,

PV = nRT

R = general gas constant (0.0821 atm.L/mol.K)

Now we will convert the mL to L.

Volume = 750 mL × 1 L/1000 mL

Volume = 0.75 L

Now we will put the values in formula.

T = PV/nR

T = 1.18 atm × 0.75 L / 0.07 mol ×0.0821 atm.L/mol.K

T = 0.885/0.00575 /K

T = 154 K

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explanation:

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