The pressure of neon changes from 786mmHg to 1811mmHg. If the initial temperature 87°C, what is the new temperature (in Kelvin Unit)?

The new temperature is 829.5 K

Explanation:

Step 1: Data given

The initial pressure of neon = 786 mmHg

The final pressure of neon = 1811 mmHg

The initial temperature = 87 °C

Step 2: Calculate the new temperature

P1/T1 = P2/T2

⇒P1 = the initial pressure = 786 mmHg  = 1.03421 atm

⇒T1 = the initial temperature = 87 °C = 360 K

⇒P2 = the final pressure = 1811 mmHg = 2.382895 atm

⇒T2 = the final temperature = ?

1.03421 atm / 360 K = 2.382895 atm / T2

T2 = 829.5 K

786/360 = 1811 / T2

The new temperature is 829.5 K

b) mutualism

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