The pressure in a bicycle tire is 66 psi at 50 ˚C in Phoenix. You take the bicycle up to Flagstaff, where the temperature is 32 ˚C. What is the pressure in the tire? (Volume and amount of moles are held constant)

Pressure in the tire is 62.32psi

Explanation:

The following were obtained from the question given:

P1 = 66 psi

T1 = 50˚C = 50 + 273 = 323K

T2 = 32˚C = 305K

P2 =?

Using P1/T1 =P2/T2 we simply calculate the new pressure as follows:

P1/T1 =P2/T2

66/323 = P2/305

Cross multiply to express in linear form

323 x P2 = 66 x 305

Divide both side by 323

P2 = (66 x 305) /323

P2 = 62.32psi

pressure in the tire is 62.32psi

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.