C6H5NH3Cl is a chloride salt with an acidic cation. If 46.3 g of C6H5NH3Cl is dissolved in water to make 150 mL of solution, what is the initial molarity of the cation

The initial molarity of cation is 2.38 M

Explanation:

To calculate the molarity of solution, we use the equation:

We are given:

Given mass of = 46.3 g

Molar mass of =  129.6 g/mol

Volume of solution = 150 mL

Putting values in above equation, we get:

1 mole of produces 1 mole of cation and 1 mole of anion

So, molarity of cation = (1 × 2.38) = 2.38 M

Hence, the initial molarity of cation is 2.38 M

- "the choice that is not an indicator of a chemical change is "state of matter changes". more common than not, chemical reactions produce energy in the form of light or heat. along with energy, they also produce a new substance called the product that could be in any state of matter (solid, gas, or liquid)."

c. 75.7

i think that is the right