White wines tend to be more acidic than red wines. Find the [H3O ] in a Sauvignon Blanc with a pH of 3.23 and a Cabernet Sauvignon with a pH of 3.64. How many times more acidic is the Sauvignon Blanc

The answers are:

[H3O] Sauvignon Blanc = 0.000588

[H3O] Cabernet Sauvignon = 0.000229

Sauvignon Blanc is 2.57 times more acid  than Cabernet Sauvignon

Explanation:

The pH is a measure to calculate the degree of alkalinity or acidity of a solution. Knowing the pH we can calculate the hydrogenation concentration of the two wines. We have to clear the equation:

pH = -log [H3O]

[H3O] = 10^-pH

Replacing we have:

[H3O] Sauvignon Blanc = 10^-3.23 = 0.000588

[H3O] Cabernet Sauvignon = 10^-3.64 = 0.000229

To calculate how many times the Sauvignon Blanc is more acidic than the Cabernet Sauvignon, we just have to divide both hydrogen concentrations, as follows:

0.000588/0.000229 = 2.57 times more acid

answer; the numbers of valence electrons in the acetic acid molecule (ch3co2h) is 24;