The combustion of propane (C 3H 8) produces CO 2 and H 2O: C 3H 8 (g) 5O2 (g) 3CO2 (g) 4 H 2O (g) The reaction of 2.5 mol of O 2 with 4.6 mol of C 3H 8 will produce mol of H 2O.

Answer : The number of moles of produced will be, 2 moles

Explanation : Given,

Moles of = 2.5 mol

Moles of = 4.6 mol

First we have to calculate the limiting and excess reagent.

The given chemical reaction is,

From the balanced reaction we conclude that

As, 5 mole of react with 1 mole of

So, 2.5 moles of react with moles of

From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of

From the reaction, we conclude that

As, 5 mole of react to give 4 mole of

So, 2.5 moles of react to give moles of

Thus, the number of moles of produced will be, 2 moles

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