Chemistry, 02.03.2020 19:17 denjayjr681

In which of the compounds below is there more than one kind of hybridization (sp, sp2, sp3) for carbon? I. CH 3CH 2CH 2CH 3 II. CH 3CH = CHCH 3 III. CH 2 = CH – CH = CH 2 IV. H – C ≡ C – H

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The compound in which there is more than one kind of hybridization (sp, sp2, sp3) for carbon is; Choice II. CH3 CH = CH CH 3 (with sp2 and sp3 hybridization)

Hybridization of orbitals is characterized by the blending of nuclear orbitals in a bid to form new hybrid orbitals whose objective is the matching of electrons to form chemical bonds in the valency bond hypothesis.

Here CH3CH = CHCH3 contains a carbon atom joined to more than 3 hydrogen atoms.

In sp – Hybridisation: the structure is usually linear since 1 s-orbital and 1 p-orbital are blended to form two sp – hybrid orbitals. In sp2 – Hybridisation: The structure is usually a planar triangular structure. 1 s-orbital and 2 p-orbitals are blended forming three sp2–hybrid orbitals. In sp3 – Hybridisation: The structure is usually tetrahedral since 1 s-orbital and 3 p-orbitals are blended forming four sp3–hybrid orbitals.

Answer from: nehamaan503

The compounds containing more than one kind of hybridization (sp, sp2, sp3) for carbon is CH3CH = CHCH3.

Explanation:

Orbital hybridization is the idea of blending nuclear orbitals into new hybrid orbitals reasonable for the matching of electrons to form chemical bonds in the valence bond hypothesis.

Here CH3CH = CHCH3 contains a carbon atom joined to more than 3 hydrogen atoms.

In sp – Hybridisation 1 s-orbital and 1 p-orbital are blended to form two sp – hybrid orbitals, having a straight structure. In sp2 – Hybridisation 1 s-orbital and 2 p-orbitals are blended forming three sp2–hybrid orbitals, having a planar triangular structure. In sp3 – Hybridisation 1 s-orbital and 3 p-orbitals are blended forming four sp3–hybrid orbitals having a tetrahedral structure.

Answer from: Quest

it is the most commonly accepted one

Answer from: Quest

The correct answer is b.hoped i you

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