When heated, KClO 3 decomposes into KCl and O 2 . 2 KClO 3 ⟶ 2 KCl + 3 O 2 If this reaction produced 71.1 g KCl , how many grams of O 2 were produced?

The correct answer is 45.9 g O₂

Explanation:

The descomposition reaction is the following:

2 KClO₃ → 2 KCl + 3 O₂

From this,, we know that 2 mol KClO₃ produce 2 mol of KCl and 3 mol of O₂. Now, we can use the molar mass of the compounds and rewrite the equation with the mass of each compound:

MM KClO₃= 39 g/mol + 35.4 g/mol + (3 x 16 g/mol)= 122.4 g/mol

2 KClO₃ = 2 mol x 122.4 g/mol= 244.8 g

MM KCl= 39 g/mol + 35.4 g/mol= 74.4 g/mol

2 KCl= 2 mol x 74.4 g/mol= 148.8 g

MM O₂= 2 x 16 g/mol= 32 g/mol

3 O₂= 3 mol x 32 g/mol= 96 g

With this, we can write a recipe in mass:

2 KClO₃   →    2 KCl  +    3 O₂

244.8 g    →   148.8 g +  96 g

244.8 g of KClO₃ produce 148.8 g. If we have 71.1 g KCl, the mass of KClO₃ from which this mass of KCl is produced is:

244.8 g KClO₃ 148.8 g KCl

          x             71.1 g KCl

x= 71.1 g KCl x 244.8 g KClO₃/148.8 g KCl= 116.97 g KClO₃

Finally, we calculate the mass of O₂ produced by 116.97 g of KClO₃ taking into account that the recipe says that 244.8 g of KClO₃ produce 96 g of O₂.

244.8 g KClO₃ 96 g O₂

116.97 g KClO₃ x= 116.97 g KClO₃ x 96 g O₂/244.8 g KClO₃

x= 45.87 g O₂= 45.9 g O₂

both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .

b. is the answer hoped i