A container of gas has a pressure of 2.76 atm at constant temperature. If the volume of the gas in the container expands from 10.0 L to 15.0 L what is the new pressure?

The new pressure 1.76 atm

Explanation:

P₁V₁/T₁ = P₂V₂/T₂

Since the temperature of the system remains constant, then we can cancel out the T₁ and T₂ to remain with;

P₁V₁ = P₂V₂

We replace the values given in the question. The unknown will be P₂

2.76 * 10 = P₂ * 15

27.6 /15 = P₂

1.76 = P₂

= 1.76 atm