How many liters of propane(C3H8) are needed to react with 15.2 liters of oxygen to produce water and carbon dioxide

3.04 liters of propane(C₃H₈) are needed to react with 15.2 liters of oxygen to produce water and carbon dioxide

Explanation:

C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

The mole ratio between the propane and oxygen in the equation is 1 : 5 as can be seen in the equation.

If the amount of O₂ reacting is 15.2 L then the amount of propane required is;

1 : 5

X : 15.2

We cross multiply the ration

5x = 15.2 * 1

X = 15.2/5

X =  3.04

= 3.04 L

8 m/s because for him to get the same amount of energy as ray is putting out, bobby, who weighs half as much as ray, needs to run twice as fast.

b.false that your answer