Pb(CH3COO)2 + H2S --> PbS + CH3COOH 1. How many moles are produced of PbS when 5.00 grams of Pb(CH3COO)2 is reacted with H2S? Make sure to show your work to get full credit. 2. What type of reaction is shown in the reaction above?

1. 0.0154mole of PbS

2. Double displacement reaction

Explanation:

First, let write a balanced equation for the reaction. This is illustrated below:

Pb(CH3COO)2 + H2S —> PbS + 2 CH3COOH

Molar Mass of Pb(CH3COO)2 = 207 + 2(12 + 3 + 12 + 16 +16) = 207 + 2(59) = 207 + 118 = 325g

Mass of Pb(CH3COO)2 = 5g

Number of mole = Mass /Molar Mass

Number of mole of Pb(CH3COO)2 = 5/325 = 0.0154mole

From the equation,

1mole of Pb(CH3COO)2 produced 1mole of PbS.

Therefore, 0.0154mole of Pb(CH3COO)2 will also produce 0.0154mole of PbS

2. The name of the reaction is double displacement reaction since the ions in the two reactants interchange to form two different products

it means there are 3 atoms of oxygen