9. A student observed the following reaction:
AICI(aq) + 3NaOH(aq) →
Al(OH),(s) + 3NaCl(aq)
After the products were filtered, which
substance remained on the filter paper?
(1) NaCl (3) AICI,
(2) NaOH (4) Al(OH),

The substance that remained on the filter paper is Al(OH).

Explanation:

Filter paper is the substance that is used in laboratory to separate the solid objects. It doesn't filter aqueous and gaseous products.So in our experiment the product formed is aluminum hydroxide Al(OH)   and sodium chloride (NaCl).Between two products, sodium chloride is in aqueous form as indicated in the question. So it wont remain in the filter paper.Hence aluminum hydroxide being only solid product remains on the filter paper.

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