Ba ( OH ) 2 Ba(OH)2 is a strong electrolyte. Determine the concentration of each of the individual ions in a 0.400 M Ba ( OH ) 2 0.400 M Ba(OH)2 solution.

[Ba^2+]= 0.400M

[OH-]= 0.800M

Explanation:

Step 1: Data given

Molarity ofBa(OH)2 = 0.400 M

Ba(OH)2 is a strong electrolyte, so 100 % dissociation

Step 2: The equation

Ba(OH)2 → Ba^2+ +  2OH-

In 1 mol Ba(OH)2 we have 1 mol Ba^2+ and 2 moles OH-

Step 3: Calculate the concentration

[Ba^2+]= 1* 0.400 M = 0.400M

[OH-]= 2*0.400 M = 0.800M