Chemistry, 29.02.2020 00:17 Dogtes9667

For the exothermic reaction
PCl3(g)+Cl2(g)?PCl5(g)
Kp = 0.180 at a certain temperature.
A flask is charged with 0.500 atm PCl3 , 0.500 atm Cl2, and 0.300atm PCl5 at this temperature.
What are the equilibrium partial pressures of PCl3 , Cl2, and PCl5, respectively?

Answers: 2

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Answers

Answer from: jayjayw64

$p_{\text{PCl3}} = p_{\text{Cl2}} = \text{0.709 atm}; p_{\text{PCl5}} = \text{0.091 atm}$

Explanation:

1. Set up an ICE table

$\begin{array}{ccccc}\text{PCl}_{3} & + & \text{Cl}_{2} &\longrightarrow & \text{PCl}_{5}\\ 0.500 & & 0.500 & & 0.300 \\ -x & & -x & & +x \\ 0.500-x & & 0.500-x & & 0.300+x \\\end{array}$

2. Write the Kp expression

$K_{\text{p}} = \dfrac{p_{\text{PCl5}}}{p_{\text{PCl3}}p_{\text{Cl2}}}$

3. Substitute the partial pressures and solve for x

$\begin{array}{rcl}\dfrac{0.300+x}{(0.500-x)(0.500-x)} &=& 0.180\\\\0.300 + x & = & 0.180(0.500-x)(0.500-x)\\0.300+x& = & 0.180(0.250 - x + x^{2})\\0.300+x & = & 0.045 - 0.180x + 0.180x^{2}\\0&= & 0.180x^{2} -1.180x -0.255\\x = \mathbf{-0.209} & & x = 6.765\\\end{array}$

We reject the positive answer, because, even if the reaction goes completely to the right, the partial pressure of PCl₅ cannot exceed 0.8 atm.

The negative sign shows that the reaction goes in the reverse direction.

$p_{\text{PCl3}} = 0.500 - x = 0.500 + 0.209 = \textbf{0.709 atm}\\p_{\text{Cl2}} = 0.500 - x = 0.500 + 0.209 = \textbf{0.709 atm}\\p_{\text{PCl5}} = 0.300 + x = 0.300 - 0.209 = \textbf{0.091 atm}$

Check:

$\begin{array}{rcl}\dfrac{0.091}{0.709\times 0.709} &=&0.180\\\\0.181 & = & 0.180\\\end{array}$

Close enough.

Answer from: VeIocity

pPCl3 = 0.709 atm

pCl2 = 0.709 atm

pPCl5 = 0.091 am

Explanation:

Step 1: Data given

Kp = 0.180

A flask is charged with 0.500 atm PCl3 , 0.500 atm Cl2, and 0.300atm PCl5 at this temperature

Step 2: The balanced equation

PCl3(g)+Cl2(g) ⇆ PCl5(g)

Step 3: The pressure at the equilibrium

pPCl3 = 0.500 - X atm

pCl2 = 0.500 - X atm

pPCl5 = 0.300 + X am

Step 4: Calculate the partial pressures

Kp = (pPCl5) / (pPCl3) *(pCl2)

0.180 = (0.300+X) / (0.500-X) (0.500-X)

0.180 = (0.300+X) / (0.250 - X + X^2)

X = -0.209

pPCl3 = 0.500 +0.209 = 0.709 atm

pCl2 = 0.500 + 0.209 = 0.709 atm

pPCl5 = 0.300 - 0.209 = 0.091 am

Kp = 0.091 / (0.709*0.709)

Kp = 0.18

Answer from: Quest

specific gravity is the density of a substance divided by the density of water. since (at standard temperature and pressure) water has a density of 1 gram/cm3, and since all of the units cancel, specific gravity is usually very close to the same value as density

so "c" is the answer

plz give brainliest

Answer from: Quest

answer: c. the experiment shows that the red substance experienced a chemical change.

explanation: chemical change is the change in which chemical composition of the substance changes. physical change is the change in which there is no change in chemical composition.

chemical changes are accompanied by following changes:

a) precipitate formation

b) energy is released or absorbed

c) formation of bubbles

d) change in color

as it is given that the red color has disappeared and there is production of gas, it means the red substance has undergone a chemical change.

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For the exothermic reaction
PCl3(g)+Cl2(g)?PCl5(g)
Kp = 0.180 at a certain temperature.<...