Write a balanced net ionic equation showing only the particles involved in the reaction and balancing the charges. Pb(s) AgNO3aq) Ag(s) Pb(NO32aq)

Pb(s) + 2Ag+(aq) → 2Ag(s) + Pb2+(aq)

Explanation:

Step 1: The unbalanced equation

Pb(s) + AgNO3aq) → Ag(s) + Pb(NO3)2(aq)

Step 2: Balancing the equation

Pb(s) + AgNO3aq) → Ag(s) + Pb(NO3)2(aq)

On the right side we have 2x NO3, on the left side we have 1x NO3.

To balance the amount of NO3 on both sides, we have to multiply AgNO3 (on the left side) by 2.

Pb(s) + 2AgNO3aq) → Ag(s) + Pb(NO3)2(aq)

On the left side we have 2x Ag, on the right side we have 1x Ag.

To balance the amount of Ag on both sides, we have to multiply Ag (on the right side) by 2. Now the equation is balanced.

Pb(s) + 2AgNO3(aq) → 2Ag(s) + Pb(NO3)2(aq)

The net ionic equation, for which spectator ions are omitted - remember that spectator ions are those ions located on both sides of the equation - will look like this

Pb(s) + 2Ag+(aq) → 2Ag(s) + Pb2+