How much energy is needed to heat a 35.5g sample of ice at -17.5°C to liquid water at
77.3°C

Q = 6831.8 J

Explanation: To solve for Q we will use the heat capacity formula:

Q= mc∆T, where the specific heat capacity of ice is ( c= 2.03 J / g°C ).

Q= 35.5 g ( 2.03 J / g°C) ( 77.3°C - (-17.5°C) )

Q= 72.065 J/ °C ( 94.8 °C)

Q= 6831.8 J

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