Anthracite is a type of coal that is composed of carbon with small amounts of hydrogen, oxygen, nitrogen, and sulfur. The formula for a sample of anthracite is C 240 H 90 O 4 NS . Calculate the amount of carbon in 40.0 kg of the sample.

The amount of carbon is 37.40 kg.

Explanation:

Molecular weight of anthracite (C240H90O4NS) = (12×240) + (1×90) + (16×4) + 14 + 32 = 2,880 + 90 + 64 + 14 + 32 = 3,080 g/mol

Molecular weight of carbon in anthracite = 12×240 = 2,880 g/mol

Mass of sample of anthracite = 40 kg

Amount of carbon = 2,880/3,080 × 40 kg = 37.40 kg

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

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