If one molecule of glucose (C6H120) reacts completely with three molecules of oxygen (O2), what is the TOTAL number of atoms
that will be in the products?
a)24
b)30
c)38
d)48

its going to be mutualism cuz they both benefit from the relationship.

~batmans wife dun dun

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

i think   the answer is c hope i'm right