A 20.00 mL Ba ( OH ) 2 solution of unknown concentration was neutralized by the addition of 42.50 mL of a 0.1255 M HCl solution. Write the balanced molecular equation for the neutralization reaction between HCl and Ba ( OH ) 2 in aqueous solution. Include physical states. molecular equation: Ba^{2+}(aq) +2OH^{-}(aq) +H^{+}(aq) +Cl^{-}(aq)<=>H_{2}O(l) +Ba^{2+}(aq) +Cl^{-}(aq) Ba 2 + ( aq ) + 2 OH − ( aq ) + H + ( aq ) + Cl − ( aq ) − ⇀ ↽ − H 2 O ( l ) + Ba 2 + ( aq ) + Cl − ( aq ) Calculate the concentration of Ba ( OH ) 2 in the original 20.00 mL solution. [ Ba ( OH ) 2 ] = M Calculate the concentrations of Ba 2 + and Cl − in solution following the neutralization reaction.

The concentration of ions in the solution are 0.0426 M and 0.0852 M respectively

Explanation:

Neutralization reaction is defined as the reaction in which an acid reacts with a base to produce a salt and water molecule.

The chemical equation for the reaction of HCl and barium hydroxide follows:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

where,

are the n-factor, molarity and volume of acid which is HCl

are the n-factor, molarity and volume of base which is

We are given:

Putting values in above equation, we get:

To calculate the number of moles for given molarity, we use the equation:

    .....(1)

Molarity of HCl solution = 0.1255 M

Volume of solution = 42.50 mL = 0.04250 L    (Conversion factor:  1 L = 1000 mL)

Putting values in equation 1, we get:

By Stoichiometry of the reaction:

2 moles of HCl produces 1 mole of barium chloride

So, of HCl will produce =

Calculating the concentration of barium chloride by using equation 1:

Moles of barium chloride =

Volume of solution = [20.00 + 42.50] mL = 62.5 mL = 0.0625 L

Putting values in equation 1, we get:

1 mole of barium chloride produces 1 mole of barium ions and 2 moles of chloride ions

So, concentration of barium ions = 0.0426 M

Concentration of chloride ions = (2 × 0.0426) = 0.0852 M

Hence, the concentration of ions in the solution are 0.0426 M and 0.0852 M respectively

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