A sample of substance X that has a mass of 326.0 g releases 4325.8 call when it freezes at its freezing point. If substance X has a molar mass of 58.45 g/mol, what is the molar heat of fusion for substance X

Answer : The molar heat of fusion for substance X is, 775.6 cal/mol

Explanation :

First we have to calculate the moles of substance X.

Given:

Molar mass of substance X = 58.45 g/mole

Mass of substance X = 326.0 g

Now put all the given values in the above expression, we get:

Now we have to calculate the molar heat of fusion for substance X.

where,

Q = heat releases = 4325.8 cal

= molar heat of fusion for substance X = ?

n = moles = 5.577 mol

Now put all the given values in the above expression, we get:

Thus, the molar heat of fusion for substance X is, 775.6 cal/mol

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.