Calculate the maximum numbers of moles and grams of H2S that can form when 153.0 g of aluminum sulfide reacts with 143.0 g of water: Al2S3 + H2O → Al(OH)3 + H2S [unbalanced]

1.02 moles of H₂S can be produced in the reaction which means a mass of 33.7 g

Explanation:

We determine the balance reaction:

Al₂S₃ + 6H₂O → 2Al(OH)₃ + 3H₂S

We have the mass of each reactant, therefore we can determine the limiting reactant. First of all we convert the mass to moles:

153 g / 150.14 g/mol = 1.02 moles of sulfide

143 g / 18 g/mol = 7.94 moles of water

6 moles of water need 1 mol of sulfide to react

Then, 7.94 moles of water may need (7.94 .1) /6 = 1.32 moles

I only have 1.02 moles, so the Al₂S₃ is my limiting reactant.

1 mol of sulfide can produce 1 mol of hydrogen sulfide (Ratio is 1:1)

Then, 1.02 moles of sulfide must produce 1.02 moles of H₂S

If we convert the moles to mass → 1.02 mol . 33.06 g/1mol = 33.7 g

We'll form 3.057 moles H2S , that is 104.2 grams

Explanation:

Step 1: Data given

Mass of Al2S3 = 153.0 grams

Mass if water = 143.0 grams

Molar mass Al2S3 = 150.16 g/mol

Molar mass H2O = 18.02 g/mol

Step 2: The balanced equation

Al2S3 + 6H2O → 2Al(OH)3 + 3H2S

Step 3: Calculate moles Al2S3

Moles Al2S3 = mass Al2S3 / molar mass Al2S3

Moles Al2S3 = 153.0 grams / 150.16 g/mol

Moles Al2S3 = 1.019 moles

Step 4: Calculate moles H2O

Moles H2O = mass H2O / molar mass H2O

Moles H2O = 143.0 grams / 18.02 g/mol

Moles H2O = 7.936 moles

Step 5: Calculate limiting reactant

For 1 mol Al2S3 we need 6 moles H2O to produce 2 moles Al(OH)3 and 3 moles H2S

Al2S3 is the limiting reactant. It will completely be consumed (1.019 moles).

H2O is in excess. There will react 6*1.019 = 6.114 moles

There will remain 7.936 - 6.114 = 1.822 moles

Step 6: Calculate moles H2S

For 1 mol Al2S3 we need 6 moles H2O to produce 2 moles Al(OH)3 and 3 moles H2S

For 1.019 moles we'll have 3*1.019 = 3.057 moles

Step 7: Calculate mass H2S

Mass H2S = moles H2S * molar mass H2S

Mass H2S = 3.057 moles * 34.1 g/mol

Mass H2S = 104.2 grams

We'll form 3.057 moles H2S , that is 104.2 grams

answer: c. the experiment shows that the red substance experienced a chemical change.

explanation: chemical change is the change in which chemical composition of the substance changes. physical change is the change in which there is no change in chemical composition.

chemical changes are accompanied by following changes:

a) precipitate formation

b) energy is released or absorbed

c) formation of bubbles

d) change in color

as it is given that the red color has disappeared and there is production of gas, it means the red substance has undergone a chemical change.

e