At what temperature would a gas have a volume of 13.5 L at a pressure of 0.723 atm, if it had a volume of 17.8 L at a pressure of 0.612 atm and a temperature of 28 C

Answer : The initial temperature of gas would be, 269.7 K

Explanation :

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

where,

= initial pressure of gas = 0.723 atm

= final pressure of gas = 0.612 atm

= initial volume of gas = 13.5 L

= final volume of gas = 17.8 L

= initial temperature of gas = ?

= final temperature of gas =

Now put all the given values in the above equation, we get:

Thus, the initial temperature of gas would be, 269.7 K