How many moles of SnCl2 will be produced if 85.3 g of FeCl3 is reacted with an excess of Sn for the following reaction:2 FeCl3(s) + 3 Sn(s) → 3 SnCl2(s) + 2 Fe(s)

The answer to your question is 0.79 moles of SnCl₂  

Explanation:

Data

moles of SnCl₂ = ?

mass of FeCl₃ = 85.3 g

excess Sn

Balanced chemical reaction

                 2 FeCl₃  +  3 Sn  ⇒   3 SnCl₂  +  2 Fe

Process

1.- Convert the mass of FeCl₃ to moles

Molar mass of FeCl₃ = 56 + (35.5 x 3)

                                  = 56 + 106.5

                                  = 162.5 g

Use proportions to find the moles of FeCl₃

                       162.5 g 1 mol

                         85.3 g  x

                         x = (85.3 x 1) / 162.5

                         x = 0.525 moles

2.- Find the number of moles SnCl₂

                     2 moles of FeCl₃ 3 moles of SnCl₂

                     0.525 moles         x

                     x = (0.525 x 3) / 2

                    x = 0.79 moles of SnCl₂                  

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