Sample of CaCO3 was heated cause causing it to form CA Oh and CO2 gas solid CAO remains behind while does CO2 escaped to the atmosphere. if caco3 weighed 612g and the caO weighed 343 g, how many grams of cO2 were formed in the reaction

The mass of carbon dioxide formed in the reaction is 269 grams.

Explanation:

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

The chemical equation for the decomposition of calcium carbonate follows:

Let the mass of carbon dioxide be 'x' grams

We are given:

Mass of calcium carbonate = 612 grams

Mass of CaO = 343 grams

Total mass on reactant side = 612 g

Total mass on product side = [343 + x] g

So, by applying law of conservation of mass, we get:

Hence, the mass of carbon dioxide formed in the reaction is 269 grams.

the answer is 1 i believe