Chemistry, 25.02.2020 02:28 Braxtonw875

The calcium content of urine can be determined by the following procedure: Ca2+ is precipitated as calcium oxalate in basic solution: Ca2+(aq) + C2O4 2(aq)  Ca(C2O4)H2O(s) After the precipitate is washed with ice-cold water to remove free oxalate, the solid is dissolved in acid, which gives Ca2+ and H2C2O4 in solution. The dissolved oxalic acid is heated to 60C and titrated with standardized potassium permanganate, KMnO4, until the purple end point is reached. 5 C2O4 2(aq) + 2 MnO4 (aq) + 16 H+(aq)  10 CO2(g) + 2 Mn2+(aq) + 8 H2O(l) (colorless) (purple) (colorless) Titration of 0.1978 g of Na2C2O4 (FW: 134.00 g/mol) required 38.65 mL of a standard permanganate, MnO4 , solution. The calcium in a 25.00 mL urine sample was precipitated by the procedure above, redissolved and required 41.35 mL of the standard MnO4  solution. What is the concentration of Ca2+ in the urine in units of mg /dL?

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