Calculate ΔH for the following reaction: N2 + 3H2 → 2NH3. Average Bond Energies N≡N, 941 kJ/mol H–H, 432 kJ/mol N–H, 391 kJ/mol HOW DO WE GET THERE? What is the total energy required to break the reactant bonds (in both N2 and H2)? Total energy required = kJ

answer;

18.5 seconds

explanation;

velocity is distance covered per unit time; it is given by displacement divided by time.

thus; time = displacement/velocity

total time = total displacement/velocity

total distance = 5000 meters south

total time = 5000/4.5

                  = 1111.11 seconds

but; 1 minute = 60 sec

thus; 1111.11 /60

                = 18.51 seconds

thus; the time taken is 18.5 seconds