A process to produce aluminum from aluminum oxide has an 85.0% yield. How much aluminum will be produced from a reaction 700.0 kg of aluminum oxide to produce Al? (assume that the reaction is Al2O3 + H2=Al+H2O

Explanation:

First you need to calculate the theoretical yield using the balanced chemical equation and the amount of aluminium available to react. Next, you use the percent yield to calculate the true yield.

1. Balanced chemical equation:

2. Mole ratios

3. Number of moles of aluminium oxide

4. Number of moles of aluminium

The mole ratio is ; thus 6,865.4 mol of aluminium oxide produce 2 × 6,865.4 mol of aluminum = 13,730.8 mol of aluminium.

5. Calculate the mass of 13,730.8 mol of aluminium

6. Calculate the actual yield

7. Convert to kg and three significant figures

answer: at room temperature (roughly 20 degrees c), you can dissolve 203.9 grams (or 200 grams) of sugar in 100 ml of water. as water temperature increases, the amount of sugar that will dissolve increases, up to about 500 grams of sugar in 100 ml water at 100 degrees c.

explanation:

idk

explanation: