Arrange the eluting power of the listed solvents in normal-phase chromatography. The highest eluting power solvent is number 1; the lowest eluting power solvent is number 3. Arrange the eluting power of the listed solvents in reverse-phase chromatography. The highest eluting power solvent is letter A; the lowest eluting power solvent is letter C. methanol (in normal phase) Answer 1 dichloromethane (in normal phase) Answer 2 ethyl acetate (in normal phase) Answer 3 diethyl ether (in reverse phase) Answer 4 water (in reverse phase) Answer 5 toluene (in reverse phase)

Explanation:

Part a

Normal Phase Chromatography

In the normal phase chromatography, the eluting power is highest for the solvent which has the highest polarity.

So from the given solvents as Methanol, Dichloromethane and Ethyl Acetate

the relative polarities are given as

Methanol=0.762

Dichloromethane (methylene chloride)=0.309

Ethyl Acetate=0.228

So the numbers are given as

Methanol :1

Dichloromethane (methylene chloride):2

Ethyl Acetate:3

Reverse Phase Chromatography

In the reverse phase chromatography, the eluting power is highest for the solvent which has the lowest polarity.

So from the given solvents as diethyl ether , water and toluene

the relative polarities are given as

Diethyl ether=0.117

Water=1.0

Toluene=0.099

So the alphabets are given as

Toluene :A

Diethyl ether: B

Water:C

d

explanation:

5.6⋅10−^19  j

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