Given the chemical equation where glucose combines with oxygen gas,
C6H12O6 + 6O2 --> 6H2O + 6CO2,
how many moles of oxygen gas will it take to use up six moles of glucose (C6H12O6 )?

6 moles oxygen gas

12 moles oxygen gas

9 moles oxygen gas

36 moles oxygen gas

Idon't know hope someone you

Answerspecies;

Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.