subject
Chemistry, 21.02.2020 23:53 ashlynchristianson

Addition of nitric acid, HNO3, and ammonium molybdate, (NH4)2MoO4, to a solution containing aqueous sodium phosphate, Na3PO4, results in the formation of a yellow precipitate of ammonium called 12-phosphomolybdate, (NH4)3PMo12O40 and two aqueous nitrate solutions: ammonium nitrate, NH4NO3 and sodium nitrate, NaNO3. Water is also formed in this reaction. Note that 12-phosphomolybdate is a very big anion! If needed, heating in a boiling water bath can increase the rate of this reaction. You will use the formation of a yellow solid on addition of HNO3 and (NH4)2MoO4 to a sample to indicate that the phosphate ion, PO43-, is present.

ansver
Answers: 3

Another question on Chemistry

question
Chemistry, 21.06.2019 18:30
Asample of the male sex hormone testosterone, c19h28o2, contains 3.88×10^21 atoms of hydrogen.(a) how many atoms of carbon does it contain? (b) how many molecules of testosterone does it contain? (c) how many moles of testosterone does it contain? (d) what is the mass of this sample in grams?
Answers: 1
question
Chemistry, 22.06.2019 02:00
Nonmetal halogen family atmoic mass 35
Answers: 1
question
Chemistry, 22.06.2019 02:00
What is the number of atoms in 3.54 mol s
Answers: 1
question
Chemistry, 22.06.2019 04:30
Long term exposure to waves can cause sunburns and skin cancer. a) visible b) infrared c) gamma rays d) ultraviole
Answers: 1
You know the right answer?
Addition of nitric acid, HNO3, and ammonium molybdate, (NH4)2MoO4, to a solution containing aqueous...
Questions
question
Mathematics, 07.08.2019 07:10
question
Biology, 07.08.2019 07:10
question
Spanish, 07.08.2019 07:10
Questions on the website: 13722366