G A hydrogen atom initially in the n = 4 states emits a photon and makes a transition to the n = 2 level. What is the wavelength of the photon in nm? (report 4 sig figs) What part of the electromagnetic spectrum does this correspond to?

The wavelength of the photon is 486.2 nm and it lies in the visible region

Explanation:

To calculate the wavelength of light, we use Rydberg's Equation:

Where,

= Wavelength of radiation

= Rydberg's Constant =

= Higher energy level = 4

= Lower energy level = 2

Putting the values in above equation, we get:

Converting this into nanometers, we use the conversion factor:

So,

As, the range of wavelength of visible light is 400 nm - 700 nm. So, the wavelength of the given photon lies in the visible region

Hence, the wavelength of the photon is 486.2 nm and it lies in the visible region

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explanation:

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2.carbon dioxide

3.helium