Iron (II) hydroxide, Fe(OH)2, is very insoluble in water. Hence, if it is produced during an aqueous reaction it will precipitate from solution. How many grams of sodium hydroxide (a strong base) must be added to 25.2 mL of a 0.605 M aqueous solution of iron (II) nitrate, in order to precipitate all of the iron as Fe(OH)2

1.2g of NaOH

Explanation:

First we put down the equation of reaction as shown in the image attached. From the equation of reaction, we can calculate the mass of sodium hydroxide that reacts with one mole of iron II ion according to the balanced stoichiometric equation. Using the information provided about the iron II nitrate, we can calculate the amount of Fe2+ that reacted with sodium hydroxide as shown in the image. Lastly, we use this information to obtain the mass of sodium hydroxide that reacted with the stipulated amount of NaOH.

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