A vacationer floats lazily in the ocean with 89% of his body below the surface. The density of the ocean water is 1025 kg/m3. What is the vacationer's average density?

The vacationer's average density is 912 kg/m³

Explanation:

Archimedes principle states that the buoyancy of an object in a liquid is equal to the weight of the liquid displaced, hence since we have

Density of sea water = 1025 kg/m³

Volume of vocationer's body below water = 89 % of total volume

Mass of seawater displaced = mass of vocationer

volume of seawater displaced = 0.89 × volume of vocationer

volume of vocationer = (volume of seawater displaced)/0.89

Density of vocationer = mass/volume = (mass of seawater displaced)×0.89/(volume of seawater displaced)

Therefore deensity of vocationer = 0.89×density of seawater

= 1025×0.89 = 912 kg/m³

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.