Five pulses are generated every 0.112 s in a tank of water. What is the speed of propagation of the wave if the wavelength of the surface wave is 1.20 cm?

The answer to the question is

The wave speed is 53.57 cm/s

Explanation:

The speed of a wave is the distance covered by the wave per unit time.

Wave speed is given by

v = f×λ

where v = The velocity of the wave

f = The wave frequency

λ = The wavelength of the wave

the speed v of the wave can also be expressed interms of the period as

v = λ/T

The freuency of the given wave is f = 5/(0.112 s) = 44.64 Hz and the wavelength is λ = 1.20 cm

Therefore the speed of the wave = 44.64 Hz × 1.20 cm = 53.57 cm/s

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.